# BECE 2019 Mathematics (Maths) Past Question Paper Two

1

## (c) If , find the value of

1. (a)
x = { 4,5,6,7,8,9,10,11,12,13}
y= {3,6,9,12,15,18}

= {6,9,12}

(b) The LCM is the smallest positive number that all of the numbers divide into evenly.
We solve this question by;

1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.

Since 3 has no factors besides 1 and 3. 3 is a prime number
Since 5 has no factors besides 1 and 5. 5 is a prime number
9 has factors of 1,3 and .

The LCM of 3,5,9 is the result of multiplying all prime factors the greatest number of times they occur in either number.

The LCM of 3,5,9 is

2

## (c) Simplify:

2. (a)
Find the LCM of 5 and 4 which is 20.
Multiply all terms by 20 and simplify (b) (i)
Boys : Girls = 12:25,
If there are 120 boys,let x be the number of girls
120 boys : x girls
12:25 = 120: x

If more, less divides
Therefore Hence there are 250 girls in the class

(ii) the total number of people in the school = Number of boys + number of girls
=250 + 120
=370

(c) Simplify: To solve, start by grouping exponential terms Simplifying.. 3

## (b) Factorize: xy+6x+3y+18.

2. (a)
Find the LCM of 5 and 4 which is 20.
Multiply all terms by 20 and simplify (b) (i)
Boys : Girls = 12:25,
If there are 120 boys,let x be the number of girls
120 boys : x girls
12:25 = 120: x

If more, less divides
Therefore Hence there are 250 girls in the class

(ii) the total number of people in the school = Number of boys + number of girls
=250 + 120
=370

(c) Simplify: To solve, start by grouping exponential terms Simplifying.. # End Of Paper

End of BECE 2019 Mathematics (Maths) Past Question Paper Two, Thank you for visiting this page, if any spelling mistake or wrong answers are spotted kindly notice us in the comment section below remember to share page to friends and famillies who may need it

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